1: Read Sum of Digits -> STL+Lambda || 列表推导

uuuouou

题目不难，可以用来练习stl和lambda

1. #include <numeric>
   
2. using namespace std;
   
3. 
   
4. class Solution {
   
5. public:
   
6.         string readSum(string &s) {
   
7.                 static const char* digit[] =  {"zero","one","two","three","four","five","six","seven","eight","nine"};
   
8.                
   
9.                 string t = to_string(accumulate(s.begin(), s.end(), int(0), [](int x,char c){ return x + c-'0'; }));
   
10.                 return accumulate(t.begin(), t.end(), string(),
    
11.                                   [=](const string& s, char c){
    
12.                                       return s.empty() ? string(digit[c-'0']) : s + " " + digit[c-'0'];
    
13.                                   });
    
14.         }
    
15. };

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用python的话可以写的更简洁且不失效率

1. class Solution:
   
2.     def readSum(self, n):
   
3.             digits = ["zero","one","two","three","four","five","six","seven","eight","nine"]
   
4.             return " ".join([digits[int(d)] for d in str(sum([int(c) for c in str(n)]))])

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